please write me the whole solution for finding the net ionic equation for potassium hydroxide and nitric acid?

Question

complete solution

Answer 1

OK....You need to understand how this is all working, and why. So, the formula equation for this reaction would be something like:

KOH(aq) + HNO3(aq) --> H2O(l) + KNO3(aq)

Since KOH, HNO3 and KNO3 are all strong electrolytes, they are totally ionized when they're dissolved in water. So, written in complete ionic form, that equation would be:

K+(aq) + OH-(aq) + H+(aq) + NO3-(aq) --> H2O(l) + K+(aq) + NO3-(aq)

To get to the net ionic equation, you just cross out the things that are the same on both sides of the arrow. K+(aq) and NO3-(aq) are on both sides, so the net ionic equation is:

H+(aq) + OH-(aq) --> H2O(l)

Answer 2

This is a reaction between a strong acid and a strong base: HNO3 + KOH -> KNO3 + H2O or, in terms of ions: H(+) + K(+) + NO3(-) + OH(-) -> K(+) + NO3(-) + H2O As in most reactions of this type, the products are a salt (potassium nitrate) and water. In terms of ions, the reactant ions are positive hydrogen and potassium cations and negative nitrate and hydroxide anions. On the products side of the reaction, there are positive potassium cations and negative nitrate anions. FYI: the Potassium hydroxide has to be standardized before it is used in the titration. This is because the solution reacts with carbon dioxide in the air, forming potassium bicarbonate. This changes the concentration of the Potassium hydroxide over time. At the end of the titration, the pH will be nearly neutral. Most strong acid/base titrations use phenolphthalein as an indicator.

Answer 3

KOH + HNO3---> KNO3 + HOH

K+OH-(aq) + H+ NO3- (aq)---> K+ NO3-(aq) + H+OH- (H2O)