A famer counts 24 heads and 80 feet. How many chickens and how many pigs?

Question

Please show your work. Sorry everyone I lost my last set of answers.

Answer 1

Chickens have 1 head and 2 feet, pigs have 1 head and 4 feet.

Let c = # of chickens, p = # of pigs.

So we have the following:

c + p = 24
2c + 4p = 80

You can solve 2 equations in 2 unknowns. Multiply the first equation by 2, then subtract it from the second to solve for p:

2c + 4p = 80
2c + 2p = 48
--------------------
0c + 2p = 32
So .... p = 16

Now substitute p=16 into your first equation to solve for c:

c+16 = 24
So ... c=8

ANSWER:
Chickens = 8
Pigs = 16

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Answer 2

Well, assuming that every chicken and pig has its head and all of its feet, set it up like this:

Let c = # of chickens
Let p = # of pigs

Since every chicken and every pig has 1 head, you can make the equation:
c + p = 24

Then, you need another equation to solve this because you have two variables.
Since pigs have 4 feet, and chickens have 2, you can set another up like this:
2c + 4p = 80

Now you have these:
c + p = 24
2c + 4p = 80

Now, multiply the ENTIRE top equation by -2 so that you can cancel out the c's.

-2(c + p = 24)
-2c - 2p = -48
2c + 4p = 80
--------------------

Now it kind of looks like an addition problem. -2c + 2c = 0, -2p + 4p = 2p, and -48 + 80 = 32

Now you have:
0 + 2p = 32
p = 16

Now since p = 16, plug that into your first equation...
c + 16 = 24
c = 24 - 16
c = 8

The farmer has 8 chickens and 16 pigs.

Answer 3

set up variables x=# of chickens y=#of pigs

x+y=24 and 2x+4y=80 (2x because chickens have 2 legs and 4y because pigs ahve 4 legs)

y=24-x then plug in the other equation

2x+4(24-x)=80 -2x+96=80 -2x=-16 x=8

y=24-8 y=16

Answer 4

Let no. of chickens be x and no. of pigs be y.since each will have only one head so x+y=24……(1)
Now total no. of chicken legs=2x
Total no. of pig legs=4y
By given condition 2x+4y=80…………(2)
Multiply(1) by 2 and subtract from second, u get
2x+4y-2x-2y=80-48
2y=32
y=16
so x=24-16=8

Answer 5

Pigs = x
Chickens = y

x + y = 24

y = 24 - x

4x + 2y = 80

Using these three equations...

4x + 2(24-x) = 80

2x = 32

x = 16

16 + y = 24.

y = 8

So, 16 pigs, and 8 chickens.

Answer 6

let c=number of chickens
and p=number of pigs
then c+p=24 eq 1
and 2c+4p=80 eq 2
multiply eq 1 by 2 so 2c+2p=48 eq 3
eq2-eq3 gives
2p = 32 so p=16 and c=8

Answer 7

let x represents chickens and y represents pigs
chickens have 2 legs, pigs have 4 legs
there are 24
2x+4y=80
x+y=24

x=24-y
sub for x: 2(24-y)+4y=80
48-2y+4y=80
48+2y=80
2y=32
y=16
because there are 24 so 24-16=8
ans: there are 16 pigs and 8 chickens

Answer 8

16 pigs, 8 chickens. Work--20 pigs is 80 feet, need fewer pigs. 16 pigs is 64 feet, yup that worked.

Answer 9

there is not sufficient information protected. operating example, 17 heads do not tell which heads might want to be pigs or poultry. And 50 feet is interior an similar condition. How might want to you delineate which feet? i might want to wager what percentage there have been, yet i might want to fairly make sure it out first.

Answer 10

8 chickens And 16 pigs...sorry i lost my homework.