Two riders on bicycles, 100 miles apart, begin traveling toward each other at the same time, one traveling 10 miles per hour and the other 15 miles per hour. A fly name Paul Revere begins flying between the bicycles, starting from the front wheel of the slower bicycle. If the fly travels 20 miles per hour flying back and forth between bicycles, being able to reverse directions without losing any time, how far will Paul Revere travel before the bicycles meet?
2006-11-12 08:01:58 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Geography
Paul Revere rode a horse.
2006-11-12 08:05:00 · answer #1 · answered by queenmaeve172000 6 · 0⤊ 1⤋
The solution is very simple. The time taken for the two bicycles to collide is 4 hrs which is derived from the equation 10t+15t=100. Hence Distance travelled by Paul Revere is 20x4=80 miles.
2006-11-12 16:45:15 · answer #2 · answered by Vijay 1 · 0⤊ 0⤋
OK
in 4 hours, bike one does 40 miles, bike 2 does 60 miles, so they meet. In 4 hours, at 20 mph the fly does 80 miles, regardless of what he is flying between. The "between the bicycles" part is to confuse us.
2006-11-12 16:19:02 · answer #3 · answered by XT rider 7 · 1⤊ 0⤋