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I need to take dimensions and get the angles that those dimensions form

2006-11-12 06:14:17 · 4 answers · asked by kimntrent 2 in Science & Mathematics Mathematics

4 answers

If u r saying that u have three sides of a triangle as a,b,c
And u want to determine angle b/w them, u can use the formula
cosA=(b^2+c^2-a^2)/2bc where A is the angle formed by the sides b and c.similarly if B is the angle formed by a and c, it can be calculated as
cosB=(a^2+c^2-b^2)/2ac
once u have calculated A and B, subtract their sum from 180, u will get third angle.
Remember u will have to use inverse table for cos to find A and B

2006-11-12 06:32:04 · answer #1 · answered by Dupinder jeet kaur k 2 · 0 0

sin(angle)= opposite/hypotenuse
cos(angle)= adjacent/hypotenuse
tan(angle)= opposite/adjacent

if your shape isn't a triangle, then divide it up into triangles. Depending on your familiarity with geometry and the Pythagorean theorem that might be harder than it sounds but you will get the answers your looking for.

2006-11-12 06:17:52 · answer #2 · answered by fleisch 4 · 2 0

Pretty vague question. You have some sort of a polygon? Can you break it into triangles or some regular poloygon and use trig. tables, pythagorian therom, etc?

2006-11-12 06:22:58 · answer #3 · answered by Richard S 6 · 0 0

what's the question?
do u mean like a hypotenuse of a triangle? Cause than it's A squared + B squared = C squared

2006-11-12 06:16:41 · answer #4 · answered by dramateen23 3 · 0 0

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