A 5.0-kg Bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s2(squared), find the force of excerted by the rope on the bucket.
If you could be so kind to show your work so i would understand i'd be very greatful
2006-11-12 05:58:29 · 5 answers · asked by hottiegirl1216 2 in Science & Mathematics ➔ Physics
Gravity will already pull on the bucket with a 9.81 m/s^2 acceleration, and it is rising with an additonal 3 m/s^2, so it total accelration is thus 12.81 m/s^2.
You know the formula F= ma?
The mass here if 5 kg. The acceleration is 12.81 m/s^2. The force will be expressed in Newton.
2006-11-12 06:10:25 · answer #1 · answered by Vincent G 7 · 0⤊ 1⤋
f = ma = F - W; where f is the net force acting on mass m = 5 kg with weight (W) to give it an upward acceleration a. Therefore, F = ma + W = ma + mg = m(a + g); where F is the upward force (positive direction) on m = 5 kg having an upward acceleration a = 3 m/sec^2 and g = 9.81 m/sec^2, the acceleration due to gravity. You can do the arithmetic.
2006-11-12 14:56:53 · answer #2 · answered by oldprof 7 · 0⤊ 0⤋
F=ma
F=5.0kg (9.8+3.0)m/s^2 (the gravitational pull of the planet plus the acceleration on the bucket
F=5*12.8=64 Newtons
2006-11-12 14:18:56 · answer #3 · answered by SteveA8 6 · 0⤊ 0⤋
Vincent is counting gravity twice. F = ma. F = 5 kg. x 3 m/s = 15 kg-m/sec
2006-11-12 14:15:38 · answer #4 · answered by Richard S 6 · 0⤊ 1⤋
you need to do your own homework, hottiegirl.
2006-11-12 14:06:21 · answer #5 · answered by Anonymous · 0⤊ 1⤋