how can i subtract 3 and 1 31/72?

Question

They're fractions!

Answer 1

You should change alll of them into improper fractions.....so.....

216/72-103/72

Your answer should equal
93/72 or 1 21/72 or 1 7/24

Hope this helps!

Answer 2

First turn the 3 into a fraction like so 3/1

Next turnthe improper fraction into a proper fraction like so: (72*1) + 31 = 103/72

Now find the least common denominator of the 2 fractions [that's the bottom number of the fraction in case you don't remember], in this case since 1 is a prime number the least common denominator is 72.

Since had to multiple 1 by 72 we must also to the same to 3 to get 216.

So now your fraction problem looks like this: 216/72 - 103/72

Subtract the two top numbers [called the numerator]: 216-103 = 113, therefore 216/72-103/72 = 113/72 = 1 41/72

Answer 3

make 1 31/72 an improper fraction and subtract from 3/1 which is the same as 3 or use a calulator

Answer 4

3 = 72*3 / 72 = 216 / 72
1 31/72 = (72*1 + 31) / 72 = 103 / 72
216 / 72 - 103 / 72 = 113 / 72 = 1 41/72

Answer 5

3 - 1 31/72
= 3 - 1 - 31/72
= 2 - 31/72
= 1 + 1 - 31/72
= 1 + 72/72 - 31/72
= 1 41/72

Answer 6

3-1 31/72
=216/72-103/72
=113/72
=1 41/72

Answer 7

change alll of them into improper fractions.

216/72-103/72


93/72 or 1 21/72 or 1 7/24

Answer 8

3 = 216/72

so 3 - 131/72 = (216-131)/72 = 85/72