2006-11-12 05:49:17 · 24 answers · asked by darren a 1 in Science & Mathematics ➔ Mathematics
2
2006-11-12 05:50:28 · answer #1 · answered by Anonymous · 0⤊ 3⤋
2
2006-11-12 06:02:16 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
It is 2
2006-11-14 03:37:07 · answer #3 · answered by Alrahcam 4 · 0⤊ 0⤋
2
2006-11-12 05:50:26 · answer #4 · answered by Anonymous · 0⤊ 1⤋
2
2006-11-12 05:50:15 · answer #5 · answered by john_stolworthy 6 · 0⤊ 2⤋
Darren,
PLEASE be careful - lots of misleading answers to your question.
Usually, we only really consider remainders when carrying out whole number division. If you are dividing (a number of cakes, say) by 3 (people, say) then the only possible remainders are 0, 1 or 2. A remainder of 3 would, of course, allow each person to get 1 more cake.
If you wanted to consider non-integer division then the uncomfortable answer is that there IS no greatest remainder. In other words, there is no "largest number which is less than 3". You can get a larger but less-than-3 number than 2.9, 2.99, 2.999, 2.9999, etc. You can get a number larger than 2.99999999and any number of nines you care to append but still less than 3. And I know that someone is going to say 2.9recurring. But 2.9recurring IS 3 (Note, is not close to 3 or just below 3 or whatever. 2.9recurring really IS 3 - people really don't like this, but it's true. Believe me).
So, if only dividing whole numbers: 2
If not whole numbers: there is no answer!
Hope this helps!
2006-11-12 10:06:24 · answer #6 · answered by Perspykashus 3 · 0⤊ 1⤋
it's 2
2006-11-12 05:51:56 · answer #7 · answered by 7 · 0⤊ 0⤋
This is easy. It's 2. If you encounter another problem like this, then just take away 1 from the number you are dividing with. Like for example, if it asks ''what is the greatest remainder you can have when you divide by 43''. Just take the 43 and take away 1 so the answer is 42.
2006-11-12 05:50:30 · answer #8 · answered by lakersforlife 3 · 0⤊ 1⤋
2/3.
2006-11-12 05:54:42 · answer #9 · answered by Polo 7 · 0⤊ 1⤋
The answer is no number at all! And not 2.9999999999------- as others have answered, remember numbers are infinite therefore the remainder is also infinite. However, there is no dispute about what digits this remainder will ALWAYS consist of and it will ALWAYS be the same digit recurring after the decimal point....... Can you think what it is?
2006-11-12 06:16:59 · answer #10 · answered by nurnord 7 · 1⤊ 1⤋