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a=V^2/r, so the larger the radius the larger the acceleration and since F=ma and assuming mass stays constant the force must increase also

2006-11-12 06:23:58 · answer #1 · answered by SteveA8 6 · 0 0

here is Newton's regulation of usual gravitation: F=G(m_1)(m_2)/r^2 F is the stress of gravity G is an extremely small consistent m_1 is one mass, m_2 is the different r is the area between the centers of hundreds. Now enable me evaluate your innovations. If the radius of the earth (yet not that is mass) replaced, that would not replace that is middle of mass, so the stress would not be any diverse. even with the undeniable fact that, it would replace the stress that the we experience through fact we would be nearer to (greater beneficial stress) or further from (lesser stress) the middle of mass of the earth.

2016-11-23 17:27:17 · answer #2 · answered by holguin 4 · 0 0

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