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What is the molarity of a solution containing 27.0 g of NH3 in 755 mL of solution?

2006-11-12 05:17:38 · 3 answers · asked by mastersource2005 5 in Science & Mathematics Chemistry

3 answers

molarity (M)=(weight/mol.weight)*(1000/volume of the solution in mL)

Now M = (27/17)*(1000//755)=2.1036 mol/lit

2006-11-12 05:37:47 · answer #1 · answered by ADITYA V 3 · 0 0

divide 27.0 g by the molar mass of NH3 and then divide that by .755 liters.

2006-11-12 14:04:48 · answer #2 · answered by The Frontrunner 5 · 0 0

27,0g NH3*(1mol NH3/ 17g NH3)= 1,59 moles of NH3
M = moles of solute/ L of solution
M = 1,59/(755mL*(1 L/ 1000 mL)= 2,10 M

2006-11-12 13:59:02 · answer #3 · answered by Chemielieber 3 · 0 0

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