If you increase the radius of something that is twirlable (like a baton) by a factor x and don't change its mass, you increase its moment of inertia by x^2. This has a couple of effects. Angular momentum is the product of applied torque and the time it is applied. The rotation rate (angular rate) is the angular momentum divided by the moment of inertia. This means that if you don't add any more angular momentum, and the object was already twirling, its rotation rate will decrease to 1/x^2 times its original rate. Or, if you want to compare the effort to accelerate the object from a motionless start to the same rotation rate as before, it takes x^2 times as much angular momentum. This last effect makes it much harder to change the direction of the rotation axis when spinning, or looking on the bright side, it will do a better job of maintaining the same spin orientation when thrown, etc. because of its x^2 greater angular momentum.
So your question has been answered, but in terms of the rotational equivalents of velocity, acceleration and force, which are angular rate, angular acceleration and torque.
2006-11-12 05:58:22
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answer #1
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answered by kirchwey 7
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here is Newton's regulation of usual gravitation: F=G(m_1)(m_2)/r^2 F is the stress of gravity G is an extremely small consistent m_1 is one mass, m_2 is the different r is the area between the centers of hundreds. Now enable me evaluate your innovations. If the radius of the earth (yet not that is mass) replaced, that would not replace that is middle of mass, so the stress would not be any diverse. even with the undeniable fact that, it would replace the stress that the we experience through fact we would be nearer to (greater beneficial stress) or further from (lesser stress) the middle of mass of the earth.
2016-11-23 17:21:26
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answer #2
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answered by Anonymous
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The larger the radius, the slower it may twirl...depending on the amount of force at the hub.
2006-11-12 05:15:23
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answer #3
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answered by Sweet 3
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