Factorise: (p + q)² + 5(p + q) please explain steps well
2006-11-12 05:07:42 · 4 answers · asked by mbchelsea 1 in Science & Mathematics ➔ Mathematics
Notice that both terms have a 'factor' of (p+q)
The first term is (p+q)*(p+q) and the second is (5)*(p+q)
So 'factor out' the (p+q) from each :
= (p+q) * [ (p+q) + (5) ]
= (p+q) * (p+q+5)
is the factorization.
2006-11-12 05:12:39 · answer #1 · answered by Scott R 6 · 0⤊ 1⤋
(p+q)^2 + 5(p+q)
=(p+q)(p+q + 5)
2006-11-12 13:29:42 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Take (p+q) as common factor, then
(p+q)[(p+q) + 5)]
Simplity
(p+q)(p+q+5)
2006-11-12 13:13:39 · answer #3 · answered by Dr. J. 6 · 0⤊ 1⤋
So let's simplify the first part
(p+q)(p+q) = p2 +2qp+q2
that means the problem is
p2 +2qp+q2+5p+5q
i think that's as good as it gets
2006-11-12 13:14:16 · answer #4 · answered by tom4bucs 7 · 0⤊ 1⤋