does anyone know how to, or can explain how i can begin to solve this problem, An unknown mass is placed on one side of an Atwoods Machine. the downward acceleration of the mass 5 kg is observed to be exactly one-half of the acceleration due to gravity. Noting that the tension in the cord is the same on each side of the pulley, determine the tension force and the unknown mass.
2006-11-12 03:51:30 · 2 answers · asked by twistoffate2099 4 in Science & Mathematics ➔ Physics
As used in this question, an Atwood machine is nothing more than a rope and pulley with masses at each end of the rope. The equations governing its operation are given in the ref. Basically, the weight difference accelerates the two masses, and the equation for that is really all you need to know:
a=(w1-w2)/(m1+m2), or
a=g(m1-m2)/(m1+m2)
2006-11-12 05:37:57 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋
by making use of descending one million.5m it lost potential potential of m g h = 6 * 9.8 * one million.5 = 88.2 J The friction of the 8kg mass is 8 * 9.8 * 0.3 = 23.fifty two N In traveling one million.5 m the gadget lost 23.fifty two * one million.5 = 35.28 J to friction. something is KE of the two hundreds. 88.2 - 35.28 = fifty two.ninety two J = (one million/2) m v^2 = (one million/2) (6+8) v^2 = 7 v^2 v = sqrt(fifty two.ninety two/7) = 2.seventy 5 m/s
2016-10-17 04:41:46 · answer #2 · answered by ? 4 · 0⤊ 0⤋