In physics, is the distance formula d = Vit + 1/2at^2 or d = Vit + at^2?

Question

where Vi = initial velocity
a = acceleration
t = time

Answer 1

the first one.
You can also double check, as all four equations of motions are interlinked.
E.g. Sub v=u+at into s = 1/2 (u+v)t
You will get s = ut + 1/2at^2.
**Note: u = Vi, while s = d. Others remain the same.

Hope this helps=)

Answer 2

no one is correct ->

we have a(t) = a , the acceleratin doesn't change -> a constant

v(t) is the integral of a(t)
So v(t) = a.t + Vi [ Vi constant ]

and d(t) is the integral of v(t) :
So d(t) = 1/2.a.t^2 + Vi.t + Di with Di initial position

as you can see the first formula can be considered as correct if we admit that Di = 0 i.e. the object is at the start point 'x=0' at the star of the time 't=0'

Answer 3

Distance = Velocity x Time + 1/2 Accel. x Time^2

Answer 4

d = Vot + ½at^2