i'm sorry i can be of no help!
2006-11-12 02:19:19
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answer #1
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answered by Anonymous
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While you have missed the actual question you can do something useful with what you have given:
V = kh^3 is the equivalent of volume proportional to cube of height.
Sub in the given values:
500 = kx10^3
k = 500 / 1000
k = 0.5
So, V = 0.5 h^3 for ANY height and volume.
So, in a typical question they will then give you a height and expect you to find the volume and then they will give you a volume and expect you to work out the height.
So, if the height of the balloon is 4m, say, then V = 0.5 x 4^3 = 0.5 x 64 = 32 cubic metres
And if the volume is 13.5 cubic metres, then h^3 = 13.5 / 0.5 = 27
So h = 3m.
Remember,
1 Write out the proportionality as an equation with a constant
2 Use your data to work out the constant
3 Rewrite the equation with the known constant
4 Use your equation to find the unknown from any given.
Hope this helps
2006-11-12 10:27:15
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answer #2
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answered by Perspykashus 3
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V = x * H cubed
if
500 = x * 10 cubed
then
500 = x * 1000
so, x = 1/2
formula is V = (H cubed) / 2
2006-11-12 10:23:38
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answer #3
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answered by ignoramus 7
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V=T*h^3 where T is a constant
we are given V=500 m^3
h=10m
T=V/h^3
=500/10^3=1/2
therefore,
V=1/2*h^3
i hope that this helps
2006-11-12 10:35:37
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answer #4
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answered by Anonymous
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V=kh^3
500=k*10^3
dividing by 10^3
k=500/1000=1/2
so the equation is v=1/2h^3
2006-11-12 10:21:47
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answer #5
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answered by raj 7
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V = k(h^3) where k is the proportionality constant.
500 = k (10^3)
k = 500/1000
k = 1/2
So the equation is:
V = (1/2)(h^3)
or
V = (h^3)/ 2
2006-11-14 20:02:50
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answer #6
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answered by Kemmy 6
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I guess you want to know what is the constant C in the equation:
V=cH
C=50 square metres.
2006-11-12 16:50:26
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answer #7
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answered by ddntruong 2
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10 x cubed ie 10x10x10=
2006-11-12 10:36:21
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answer #8
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answered by CLIVE C 3
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Yes, I am quite brainy, but I don't do maths! I hope this has answered your question.
2006-11-12 10:29:00
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answer #9
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answered by apple84 3
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no idea,but tks for the 2 pts. lol :P
2006-11-12 10:25:43
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answer #10
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answered by forest lover 2
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What exactly are you asking?
2006-11-12 10:28:15
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answer #11
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answered by robbet03 6
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