I will be visiting friends there for a family party and they do not have enough room to have every one to stay overnight. I've stayed in lovely hotels before on business trips, but can't afford them on my own account. I would like somewhere comfortable and convenient for central Birmingham or Moseley/Hall Green area.
2006-11-12 02:12:51 · 8 answers · asked by Bridget F 3 in Travel ➔ United Kingdom ➔ Birmingham
You're probably best trying a Travelodge or Premier Travel Inn as they are cheap and decent to stay in, there some located in the city centre and in the outskirts of the city centre.
2006-11-13 05:00:05 · answer #1 · answered by emmalp75 3 · 0⤊ 0⤋
trip hotels , it extremely is barely an somewhat short taxi experience from maximum places. you desire to stay over , so which you will drink??? on an identical time you like those form of centers? sounds like an somewhat long night? ok, we wont flow into that, the situation i'm thinking approximately is interior the Queensway section. Have a robust trip.
2016-12-14 05:49:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋
somewhere cheap then..well thatlll be coventry. try in meriden, or away from the airport... cov is only 20 minutes away...and a damn sight cheaper. theres the post house at allesley, 10 mins away..£ 45 a night
or you can try B&B which is around 15-20 quid a night.
2006-11-12 02:19:22 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The Malmaison in the city centre is pretty good.
2006-11-12 02:18:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
don't know if this is local enough for for you but i stayed a brilliant place the thistle group i think it was luxury ask the prices you may be surprised its a lot cheaper than we think
2006-11-12 02:16:16 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Travel lodge.
2006-11-12 02:20:37 · answer #6 · answered by Rich S 5 · 0⤊ 0⤋
Nice! Birmingham! shurely not in the same sentence?
2006-11-12 04:46:29 · answer #7 · answered by dave a 5 · 0⤊ 3⤋
try a travel site
2006-11-12 02:22:03 · answer #8 · answered by jimmyc1163 3 · 0⤊ 0⤋