A piece of cheese is at rest. A gerbil pulls to the left with 1.5 N at the same time as a mouse pulls to the right with 1.5 N.
a) what is the net force on the piece of cheese? 0 N
b) What does the cheese do in this situation? choose ALL that apply:
moves with constant non-zero velocity
accelerates at a constant rate
remains at rest
maintains constant velocity
speeds up
moves with a changing velocity
slows down
2006-11-12 01:40:35 · 5 answers · asked by vintagex50s 2 in Science & Mathematics ➔ Physics
Serious answers only please.
2006-11-12 01:54:34 · update #1
Since the piece of cheese is at rest. and no net force is acting. by Newton's First Law of Motion, it would continue in its initial 'state of motion' which is rest here (since it was initially at rest) ....all other choices would violate the law!. got it dear!
2006-11-12 02:10:09 · answer #1 · answered by usarora1 3 · 0⤊ 0⤋
The net force would be zero, but you would need more detail to answer the second question. If both forces were along the same axis then the system would be static (forces cancel each other out, a=0 v=0). However if the forces were offset (i.e. gerbil pulls the top of the block of cheese and the mouse pulls the bottom) then there would be a moment force on the cheese which would cause the cheese to rotate with a constant acceleration but not velocity. There are a couple other cases that are possible but these two would be the most common.
2006-11-12 03:43:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
into 3 pieces, 1 in the gerbil's beak, 1 in the mouse's mouth, & the bigger piece in the same place
2006-11-12 01:52:27 · answer #3 · answered by Dreamweaver 5 · 0⤊ 0⤋
accelerates at a constant rate (acceleration rate = 0)
remains at rest
maintains constant velocity (velocity = 0)
2006-11-12 01:57:49 · answer #4 · answered by Marker 4 · 0⤊ 0⤋
remains at rest since all the forces are equally balanced that is we can say that system is in equilibrium
2006-11-12 01:55:31 · answer #5 · answered by Mysterious 3 · 0⤊ 0⤋