I think that the domain is all real numbers because the graph can go on and on with no restrictions. The range I am unsure how to calculate.
2006-11-12 01:00:22 · 3 answers · asked by jonesin_am 1 in Science & Mathematics ➔ Mathematics
I think that the range is (-9 +or- sqrt2)...anybody agree?
2006-11-12 01:08:57 · update #1
uhh,,i will have to ask my maths teacher in college,,
thanx for the superb question,,
2006-11-12 01:07:19 · answer #1 · answered by kp 2 · 0⤊ 1⤋
-sqrt 2 cos(6x+1)-9
X can be an value so domain is all real numbers. x can be -1/6 as this just makes cos(6x+1) =cos (0) = 1..As x varies, cos(6x +1) varies between a max of +1 and a min of -1.
Thus the range is between -sqrt 2 (1) - 9 = -sqrt 2 -9 and
-sqrt 2 (-1) -9 =sqrt 2 - 9.
2006-11-12 09:54:03 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
i feel x cannot be -1/6 as ix x=-1/6,6x+1 will be zero and
1/(6x+1)^9 will be indeterminate
2006-11-12 09:06:58 · answer #3 · answered by raj 7 · 0⤊ 1⤋