yes, but she's only in her 20's
2006-11-12 00:47:13
·
answer #1
·
answered by Anonymous
·
1⤊
0⤋
YES! She has been around a long time, you know - she made her first album with Sony when she was 13. She's incredibly popular, and she's been breaking all sorts of records. For example, "La Tortura" was the first Spanish-language video to enter regular rotation on MTV. And "Hips Don't Lie" is the most played song in history. She is extremely talented - she has a repertoire of over 80 songs, not just "Hips Don't Lie" and "Whenever Wherever."
2006-11-12 12:41:17
·
answer #2
·
answered by Heidi 7
·
1⤊
0⤋
Shakira's very talented:she sings very good and she's a very talented dancer too.I think she'll be able to sing even when she'll be 40 cause she has lots of talent.
2006-11-12 09:34:14
·
answer #3
·
answered by black_cat 6
·
3⤊
0⤋
Of course it will....YES IT WILL...GO SHAKIRA!!!!....
HERE IS A CLIP OF SHAKIRA's that you will love
It's a clip where she moves her body (belly) in a downward-wave like motion that is simply incredible.
Watch frame 00:26sec-00:40s it is very worth it
http://www.youtube.com/watch?v=nFkW-bReI0c
you can buy the DVD at amazon, barnes and noble...it's called "SHAKIRA; Live and Off the Record"
2006-11-14 17:34:36
·
answer #4
·
answered by christiansareawesome 4
·
0⤊
0⤋
will last in 5 year
2006-11-12 09:23:59
·
answer #5
·
answered by gunesumut 2
·
0⤊
1⤋
Her talent is in her hips, and the way she thrashes herself around they won't last another 15 years.
2006-11-12 08:58:45
·
answer #6
·
answered by ? 6
·
0⤊
3⤋
No way. Her talent is being ridiculously sexy, but she has a voice like a foghorn. When the body goes, she'll vanish.
2006-11-12 08:53:41
·
answer #7
·
answered by Katya-Zelen 5
·
0⤊
3⤋
Oh yeah definitely!! She even looks younger every time I see her!!
2006-11-13 19:07:48
·
answer #8
·
answered by ♥Stranger In Maine™♥ (Thriller) 7
·
1⤊
0⤋
no shell break her hips and end up in the hospital 4 the rest of her life. plus she cant sing.
2006-11-12 09:21:19
·
answer #9
·
answered by kassidysummers 1
·
0⤊
3⤋