what is the orbital angular momentum in 3d orbitals?

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2006-11-11 23:09:06 · 5 answers · asked by charu 1 in Science & Mathematics ➔ Physics

The angular change ratio from the planar field

2006-11-11 23:52:39 · answer #1 · answered by Anonymous · 1⤊ 0⤋

It is from Keplerian dyanmics of planetary motion the angular momentum is del dot Sinetheta.

2006-11-13 12:45:33 · answer #2 · answered by Mathew C 5 · 0⤊ 0⤋

I think the formula is mvr=nh/2*3.14

so,for a 3d orbital it should be:

3h/2*3.14

2006-11-12 09:11:15 · answer #3 · answered by sai chetan 2 · 0⤊ 0⤋

the formula is = {l(l+1)}^1/2 *h/2pi
=6^1/2*h/2pi

2006-11-12 10:46:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋

Please, clarify! What do you call "3d orbitals" ???

2006-11-12 07:43:50 · answer #5 · answered by just "JR" 7 · 0⤊ 0⤋