i can gt to to 1/cotB = secB but from there i am stuck! please help i have an exam tomorrow!
2006-11-11 22:36:37 · 6 answers · asked by lucy_goose 3 in Science & Mathematics ➔ Mathematics
csc B * tan B = sec B
csc = 1/sin (By definition)
tan = sin/cos (By definition)
Making those substitutions...
(1/sin B) * (sin B/cos B)
The sin B's cancel out and you're left with 1/cos B = sec B.
2006-11-11 22:44:46 · answer #1 · answered by JoeSchmo5819 4 · 0⤊ 0⤋
LHS = cosecB*tanB
= (1/sinB)*(sinB/cosB)
= 1/cosB
= secB
= RHS
hence proved.
2006-11-12 07:54:44 · answer #2 · answered by oee22 2 · 0⤊ 0⤋
cosecB = 1/sinB
tanB = sinB/cosB
LHS = cosecB * tanB = (1 / sinB) * sinB / cosB = 1 / cosB = secB = RHS.
2006-11-12 06:44:34 · answer #3 · answered by PSV 2 · 0⤊ 0⤋
cosecB = 1/sinB
tanB = sinB/cosB
=> tanBcosecB = 1/cosB
now 1/cosB = secB
prob solved
2006-11-12 06:47:20 · answer #4 · answered by Charu Chandra Goel 5 · 0⤊ 0⤋
when in doubt reduce everythingto the basicratios of sin and cos
cosecB=1/sinB
tanB=sinB/cosB
secB=1/cosB
LHS=cosecBtanB
=1/sinB(sinB/cosB)
=1/cosB
=secB
=RHS
hence proved
2006-11-12 06:49:03 · answer #5 · answered by raj 7 · 0⤊ 0⤋
cosecB tanB
=1/sinB *sinB/cosB
=1/cosB [sinB and sinB will obsolute]
=secB
2006-11-12 06:55:54 · answer #6 · answered by sanu 2 · 0⤊ 0⤋