English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

how many moles of argon r present in a 4.00 liter container @ a pressure of 375mlhg. @ 20 degree celcius

2006-11-11 18:27:13 · 3 answers · asked by pearl 1 in Science & Mathematics Chemistry

3 answers

0.0821 moleP1V1/T1=P2V2/T2
375*4/293=760*V2/273.5
V2=375*4*273.5/(293*760)
22.4 litres contains 1mole
375*4*273/293*760
=375*4*273/293*760*22.4
=0.0821 mole

2006-11-11 18:48:41 · answer #1 · answered by raj 7 · 0 0

(1 mole/22.4 L)(4 L)(760 mm/375mm) = 0.3619 mole

2006-11-11 18:44:18 · answer #2 · answered by Helmut 7 · 0 0

(1mol*K*4.0L*1atm*375mmHg)/
(.082058L*atm*293K*760mmHg)
=.0821moles

you need to convert your degrees celcius into kelvin
20+273=293 K

1mol*K/.082058L*atm is a constant

all your units cancel and you are left with moles.

2006-11-12 11:14:16 · answer #3 · answered by Ruiz 2 · 0 0

fedest.com, questions and answers