Fill in the blanks Part 2: Show your solution?

Question

a. 9 = 16 x __ + 51

b. 2 x __ - 8 = 14 - 9 x __

c. 3 x __ + 5 = 9 x __ +2

Answer 1

We can use faux-algebra to solve these. You probably haven't taken algebra yet. With algebra these would be extremely easy to solve. It's why algebra was invented.

a. 16 x ___ has to be -42, because if we add 51 to it we get 9. Thus, ____ has to be -42/16, or -21/8.

b. 2 x ____ has to be 22 - 9 x _____, because if we subtract 8 from it we get 14 - 9 x ____. And 22 has to be 11 x ____, because if we subtract 9 x ____ from it we get 2 x ____. Thus, ____ has to be 22/11, or 2.

c. 9 x ___ has to be 3 x ____ + 3, because if we add 2 to it we get 3 x ___ + 5. And 3 has to be 6 x ____, becuase if we add 3 x ____ to it we get 9 x ____. Thus, ____ has to be 3/6, or 1/2.

With algebra, no such thinking would be required. You just plug in the formulas and grind away. You'll see when you study algebra.

Answer 2

a. 9=16*(-42/16)+51.
b.2*11-8=14-9*0.
c.3*5+5=9*2+2.

Answer 3

a. 3/8 - one million/4 x __ = one million/6 -one million/4 x __ = one million/6 - 3/8 -one million/4 x __ = 4/24 - 9/24 one million/4 x __ = 5/24 one million/4 x 5/6 = 5/24 b. 2/3 - 3/5 x __ = 2/5 x __ + 4/3 -3/5 x __ = 2/5 x __ + 4/3 - 2/3 -3/5 x __ - 2/5 x __ = 2/3 with the aid of fact the __ are the two the comparable quantity in the top, they could be mixed -one million x __ = 2/3 -one million x -2/3 = 2/3

Answer 4

Just place 'X' as the unknown in each blank, and reduce the equations (both sides), i.e. solve for X.