Here is the problem:
(x+2)(x-5)=(x-1)(x-3)
I just keep forgetting how to do it. The answer in the book says that it's 13. But I keep getting a complete different answer.
2006-11-11 14:40:47 · 4 answers · asked by snape_fan_2005 2 in Education & Reference ➔ Homework Help
(x+2)(x-5)=(x-1)(x-3)
x^2-3x-10=x^2-4x+3
-3x-10=-4x+3 [x^2's cancel]
+3x +3x
-10=-x+3
-3 -3
-13=-x
x=13
2006-11-11 14:45:30 · answer #1 · answered by m3_mY$3Lf_! 4 · 0⤊ 0⤋
x^2 - 5x +2x - 10 =x^2 -3x -x + 3
x^2 - 3x -10 = x^2 - 4x +3
x^2 -x^2 -3x +4x = 3 +10
x =13
2006-11-11 14:49:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You have to foil both sides
mulitply the first two , then the outside two and then the inside two , and the last two
2006-11-11 14:47:36 · answer #3 · answered by sam 2 · 0⤊ 0⤋
(x+2)(x-5)=(x-1)(x-3)
x^2-5x+2x-10=x^2-3x-x+3
x^2-x^2-5x+2x-10=x^2-x^2-3x-x+3
-5x+2x-10=-3x-x+3
-3x-10=-4x+3
-3x+4x-10=-4x+4x+3
x-10=3
x-10+10=3+10
x=13
Cheers!
C
2006-11-11 15:45:41 · answer #4 · answered by Mysterious 3 · 0⤊ 0⤋