5z(to the 2nd power)+4z-12
Does anyone know the answer?
2006-11-11 13:16:32 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Thank you SO MUCH MollyMAM!
2006-11-11 13:28:15 · update #1
I'm assuming you want to factor this
5z^2 + 4z -12 = (5z -6)(z+2)
2006-11-11 13:24:36 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
We call this " tasukigake " in Japan.
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5z^2+4z-12=(z+2)(5z-6)
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2006-11-11 21:30:30 · answer #2 · answered by atomonados 1 · 1⤊ 0⤋
5z^2+4z-12=0? I assume you want it to =0
(5z-6)(z+2)=0
5z-6=0
z=1.2
z+2=0
z=-2
2006-11-11 23:23:47 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
uhhh
5z x 5z + 4z - 12
25z + 4z - 12
29z -12
17z
i think... :o)
2006-11-11 21:19:51 · answer #4 · answered by Thrills 5 · 0⤊ 2⤋
the answer is 29z-12 you cant simplify
2006-11-11 21:19:57 · answer #5 · answered by Mimzy 2 · 0⤊ 2⤋
yes now do your own homework
2006-11-11 21:18:00 · answer #6 · answered by TrOpPo 3 · 0⤊ 0⤋
Apply this: ( -b^2(+ or -)sqrt(b^2-4ac) ) / 2a
2006-11-11 21:27:24 · answer #7 · answered by Anonymous · 0⤊ 1⤋
0_0uuuuuuuuuuuuuuuuuuuuuuuuuhhhhhhhhhhhhhhhhhhhhhhhhh...........................................................................................................OW!!!!!!!!MY HEAD HURTS.*8^>
2006-11-11 21:21:16 · answer #8 · answered by Ichigo 1 · 1⤊ 2⤋