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The equivalency principle of Einstein says that inertial mass is eqivalent to gravitational mass so both can have same acceleration or weight at any speed?

2006-11-11 12:12:00 · 5 answers · asked by goring 6 in Science & Mathematics Physics

5 answers

According to Mark McCutcheon who sort of justifies why Einstein’s Theories of Relativity are flawed, and according to his Expansion Theory of the Universe, here is what he says in his book The Final Theory:

“Warp speed has been within our grasp ever since the early days of the space program. We simply have not achieved it because we haven't tried, and we haven't tried because Special Relativity Theory said we couldn't – and we believed it. All that is required is continuous acceleration from an extended fuel burn; a spaceship would accelerate faster and faster as its fuel burns, just as common sense tells us it should. The spaceship will not undergo a mysterious "relativistic mass increase" as it increases in speed, it will not need to burn more and more fuel to compensate for such "mass increase," and it will not have any special difficulty approaching or exceeding the light-speed "barrier." ”

Now, you can imagine the implications for these particle accelerators which apparently cannot accelerate particles at speeds beyond the speed of light because their weight or relativistic mass reaches infinity. McCutcheon states:

“The "energy" used to accelerate the particles is supplied by electromagnets that are timed to pulse as the particles pass by, giving them a boost. However, as shown in the previous chapter, a magnetic field is actually a cloud of expanding electrons. If each pulse sends a cloud of electrons expanding toward the passing particles at the speed of light to give them a push from behind, it is not surprising that the particles are accelerated less and less as they speed by faster and faster. As the particles approach light-speed they would be shooting past almost as rapidly as the electron clouds would be expanding behind them. The expanding electron clouds would barely be able to catch up with the particles as they pass, and so, would only be able to give them a tiny additional boost that gets smaller still as the particles get even closer to light speed.”

“Increasing the energy input simply means producing denser electron clouds from the pulsing magnets, which improves the efficiency of each boost (makes each push more solid) but does not increase the speed of expansion of these electron clouds. Therefore, as ever more energy is put into the system, the passing particles receive ever more solid nudges toward light-speed but still can never exceed the speed of light since this is the limit of the speed boosts. This need not be considered as validation of the mysterious "relativistic mass increase" concept of Special Relativity Theory, but merely as an expected result once the true nature of magnetic fields is understood.”

And yet, we’re going to create micro-singularities soon, or micro black holes, in the new Large Hadron Collider at CERN in 2007. So we’re going to accelerate the particles even closer to the speed of light, and that will be enough? Who knows...

2006-11-14 02:49:36 · answer #1 · answered by RM 1 · 0 1

As the object approached the speed of light, it would increase to near infinity mass. If you accelerated it to the speed of light, it would need increasing energy and when it was traveling at the speed of light would littler cause the object to expand indefinitely, the other theory is that in order to make mass travel at the speed of light it would have to be the equivalent of light. With this in mind you could say that moving any mass at the speed of light would cause you to ether rip apart or blow up like a balloon think of it like a pebble in the water if it where to move faster and faster it's mass would expend, soon all you would have is a rock with no water.
Mass/sqrt(1-v^2/c^2) = Light *Mass
Light is the Factor = 1/sqrt(1-v^2/c^2)
M=mc^2 dose not work here mass must equal light^2

2006-11-11 13:53:40 · answer #2 · answered by matt v 3 · 0 1

From a previous answer of mine:

let:
Mo = resting mass
c = speed of light
v = current speed
sqrt = square root

Then M (moving mass) = Mo/sqrt(1-v^2/c^2) = L*Mo

L is the Lorentz Factor = 1/sqrt(1-v^2/c^2)

M, the moving mass is called the relativistic mass

Note the energy to move is E = L*Mo*c^2 so as v approaches c the Lorentz factor goes to infinity and so does E. Most people write E = Mc^2 but this M is equal to L*Mo

Also note that when you move (even at slow speeds) your mass goes up just a small fraction.

2006-11-11 12:59:19 · answer #3 · answered by ic3d2 4 · 0 0

As the object approached the speed of light, it would increase to near infinity mass. If you accelerated it to the speed of life, it would need increasing energy (to almost infinity) and when it was traveling at the speed of light it would transform into energy

2006-11-11 12:31:35 · answer #4 · answered by Scarp 3 · 0 0

The mass of an merchandise relies upon upon who's gazing it. specifically, how briskly they're traveling relative to you. What E=MC^2 somewhat potential is that potential and mass are 2 factors of the comparable coin. What you spot as "mass" is definitely merely "frozen potential". there is this "stuff" that exists, and mass and potential are 2 interchangable styles of it. think of of it this way. Say you're in a commute going one million m/s slower than the fee of light. you place your foot on the gas pedal. What occurs? you may not merely save increasing velocity indefinitely, and that potential has to bypass someplace. So it is compelled to bypass into mass.

2016-10-17 04:13:07 · answer #5 · answered by janovich 4 · 0 0

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