who will score more points...
2006-11-11 11:55:50 · 7 answers · asked by phu3210 2 in Sports ➔ Fantasy Sports
David Garrard at QB
Kellen Winslow at TE
2006-11-11 12:01:08 · answer #1 · answered by Al J 4 · 0⤊ 0⤋
Garrard made the most of his chances last week against Tennessee, completing 12-of-22 passes for 177 yards and three TDs. He will start again this week and has another favorable matchup as the Texans rank 23rd against the pass. They gave Leftwich fits last time, but look for Garrard to patiently execute this game plan better at home.
Wow, what a season Winslow is having in 2006. He had a career-high 11 catches last week for 78 yards and now leads all tight ends with 51 catches for 471 yards and three TDs. Against the league's 31st ranked pass defense, Winslow could have another big game as he's a MUST start
I'm not even going to say anything about the two remaining players, no contest.
I'm even thinking of picking up Garrard myself, as he is available in my league. This week I think he will have a good one!
Frank C
2006-11-11 12:24:10 · answer #2 · answered by Frank C 2 · 0⤊ 0⤋
Garrad and Winslow.
Garrad is a better quarterback than Seneca and faces a weaker defense than Seneca does.
Winslow is questionable but he will play since he practiced Thursday and Friday. He has had the most receptions by a TE BY FAR this year. With Donte Stallworth back look for LJ Smith's production to go down some.
2006-11-11 13:24:10 · answer #3 · answered by dandaman264 2 · 0⤊ 0⤋
Garrard and Smith... Winslow is not going to do as much as Smith because the eagles are facing a team that have SOOOO much trouble with tight ends
2006-11-11 12:04:25 · answer #4 · answered by neal0113 2 · 0⤊ 0⤋
Garrard and Winslow
2006-11-11 11:56:59 · answer #5 · answered by CJ 6 · 0⤊ 0⤋
Winslow may not play so I would go with Smith or check on his status tomorrow.
2006-11-11 11:58:52 · answer #6 · answered by Anonymous · 1⤊ 0⤋
David Garrard, unless they are playing a really good team.
2006-11-11 11:58:34 · answer #7 · answered by Wocka wocka 6 · 0⤊ 0⤋