maths troubles - calculas - please please help me?

Question

can anyone help me with this - I was told to integrate

y= e^2x / √1-e^2x


anybody, please

thats ("y" is equal to "e" to the power of 2x) over (the squareroot of 1 - "e" to the power of 2x)

Answer 1

Okay, assuming you mean:
∫e^(2x)/√(1-e^(2x)) dx
Let u=1-e^(2x), du=-2e^(2x) dx, dx = -1/2 e^(-2x)
-1/2 ∫1/√u du
-1/2 ∫u^(-1/2) du
-u^(1/2) + C
-√(1-e^(2x)) +C

Answer 2

y= e^2x / √1-e^2x
=(e^2x)/[(1-e^x)^(1/2))]
=(e^2x)/[(1)^(1/2)-(e^x)^(1/2)]
=[(e^2x)/[(1)^(1/2)]-[(e^2x)/[(e^x)^(1/2)]