would this be correct?

Question

if I have a energy source of 200v and a light bulb of 130 v, the potentital difference of the lightbulb through the reading of a voltmeter be 200v?

Same energy source but now with a 130v and 120v light bulb would the potential difference of the 130v bulb be 104v and the 120v bulb be 96v?

Answer 1

Energy is measured in watts, so I assume you mean a voltage source of 200v.

(1)
The voltage source of 200v applied to the light bulb (laminar) will be 200v. Since the light bulb is designed for 130v, the supply voltage will likely blow the bulb.

(2)
Here you have two possibilities, depending on your circuit.
(a) If you have a parallel circuit, then each light bulb will have 200v across it, and again the bulbs will likely blow because the voltage is to high.
(b) If you have a series circuit, the voltage across the light bulbs will be subject to their resistance. Assuming the resistance is the same, then the voltage will be the same, that is, 100v each.
The voltage across each light bulb will be equally proportional to it's resistance ratio.

Answer 2

Hi, if you connect a 130V designated light bulb to a 200V outlet, it will most likely flash up once and be dead for the rest of the days.

The 130V written on the bulb does no designate something like a voltage limiter or so. So you wont see a potential difference.

Answer 3

First, voltage is not an energy. The SI unit for voltage is defined as:

V = kg*m^2/(A*s^3)

Clearly not an energy, which is a Joule = kg(m^2/s^2)

Anyway, you have a voltage rating for the bulbs, and the source. It's not clear what you are asking.

The POTENTIAL across either bulb is the applied 200 volts. However the voltage *drop* across each depends on their resistance, either separately or in some combination.

The configuration of their combination makes a difference and so does the voltage type...AC (alternating current) or DC (direct current).

If you can provide some of this information you may stand a chance of receiving legitimate responses to your question.

Answer 4

Generally in these sort of questions light bulbs are measured in Watts and Ohms, but I suppose I can see what they are getting at. So the answer is yes, you just pro-rata the input voltage (200) across the two light bulbs.
So its (200/250)x130 = 104 and (200/250)x120 = 96.

I think in the first experiment the 130V bulb would have glowed very bright and died of a surfeit of volts.