I need to find y' for this equation. y=(2*sqrt(xy)-y)/(4*sqrt(xy)+x)?

Question

I don't know why it dodn't display all of the equation. I must have ran out of characters. the equation is y=(2*sqrt(xy)-y)/(4*sqrt(xy)+x)
Also I don't need a numaric value I need y' (y prime) and I already did the problem 3 times and It has been wrong every time. I am not trying to cheat or be lazy, I simply need help.

If you scroll your mouse over the equation it will tell you all of it.

Answer 1

I agree with birchardv here...........we need the rest of the problem, and you would learn a lot more if you did the homework yourself. But do whatever floats your boat. Add the rest of the problem and I'll get back to you.

Okay Chemist, this problem is really long; if you want a good answer with plenty of steps, I'll need more room. Email me and I'll send you the solution.

Answer 2

needless to say y and z can not the two be even by way of fact this makes LHS even and RHS unusual. Can y, z be equivalent? if so then x*y^2 = 2y^2 + a million ----> (x - 2)*(y^2) = a million and clearly x = 3, y = a million is the only answer with integers. any further i visit think of that y is the bigger of y, z as reversed techniques are extremely an identical. Can z = a million be a answer with out y = a million? xy = y^2 + 2 ----> y^2 - xy + 2 = 0 ----> y = [x + sqrt(x^2 - 8)]/2 x = 3 ends up in y = 2 so x = 3, y = 2, z = a million is a answer with all 3 distinctive. Can z = 2? 2xy = y^2 + 5 ----> y^2 - 2xy + 5 = 0 ----> y = [2x + sqrt(4x^2 - 20)]/2 = x + sqrt(x^2 - 5) This has answer x = 3, y = 5, z = 2. For sqrt(x^2 - 5) to be an integer we want x^2 - 5 = ok^2 yet 2^2 and 3^2 are the only squares differing via 5 so this ends up in no different techniques. I surely have chanced on, yet won't positioned the evidence right here, that z (the smaller of y, z remember) won't be able to be 3 or 4. This makes me suspect that there are no longer the different techniques. EDIT. That final line is inaccurate! i've got merely chanced on that x = 3, y = 13, z = 5 is a answer. although, it is looking as though x ought to be 3.

Answer 3

Sounds like you've not stated an equation anyone here can solve. I suspect you'd be better off doing your own homework, since you are more likely than we to:

1 Know the full problem.
2. Benefit from the exercise

Good luck

Answer 4

I will need to see the full problem to solve it. Also, you will need a second equation if you want a numerical answer. This equation is already solved in terms of y.

Answer 5

You need to edit your question so it displays the entire function.