what is the result of hydroboration of propene followed by oxidation with HOOH (in basic conditions)?
thanks
2006-11-11 07:43:58 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
1-Propanol. CH3CH=CH2 + B2H6 ===> CH3CH2CH2-BH2 ===> CH3CH2CH2-OH.
Diborane always adds with the H on the more highly substituted carbon. This is the opposite of the Markovnikov rule during reaction with H2O and a little H2SO4, where the H goes to the less highly substituted carbon to give 2-propanol.
2006-11-11 08:04:26 · answer #1 · answered by steve_geo1 7 · 1⤊ 0⤋
I think 1-propanol (propan-1-ol) would result.
2006-11-11 08:03:29 · answer #2 · answered by prune 3 · 0⤊ 0⤋
CH3CH=CH2 + BH3 --H2O2--> CH3CH2CH2OH
propene ------------> 1-propanol
2006-11-11 08:03:04 · answer #3 · answered by titanium007 4 · 0⤊ 0⤋
A strange "eggy" smell.
2006-11-11 07:45:16 · answer #4 · answered by Jotun 5 · 0⤊ 0⤋