dimensions of the largest isosceles triangle that can be inscribed in a circle with a radius of 4. height=h
2006-11-11 07:35:07 · 5 answers · asked by crazy baby 1 in Science & Mathematics ➔ Mathematics
let the base of the isosceles triangle be x
height of the triangle=h
given the radius of the circle is 4
(4-h)^2+(x/2)^2=4^2
16-8h+h^2+x^2/4=16
4h^2-32h+x^2=0
x=rt(32-4h^2)
area=1/2*x*h
=1/2*h[2rt(8-h^2)]
dA/dh=0 for max
after finding h sub to get x
2006-11-11 07:49:29 · answer #1 · answered by raj 7 · 0⤊ 0⤋
55
2006-11-11 15:37:59 · answer #2 · answered by 100% Español 5 · 0⤊ 0⤋
r = a*sqrt(3)/6 and r = 4 =>h = 8*sqrt(3).
2006-11-11 15:43:27 · answer #3 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
You really should do your own homework. You won't have Yahoo! Answers when you take your exam.
2006-11-11 20:08:44 · answer #4 · answered by mathematician 7 · 0⤊ 0⤋
sorry
2006-11-11 15:39:13 · answer #5 · answered by shiny 1 · 0⤊ 0⤋