What mass of aspirin is produced by the reaction of 40.0g of salicylic acid and 30.0g of acetyl chloride?

Question

Aspirin (C9H8O4) can be made in the laboratory by reacting salicylic acid (C7H6O3) with acetyl chloride (C2H3ClO). What mass of aspirin is produced by the reaction of 40.0g of salicylic acid and 30.0g of acetyl chloride?
C7H6O3 + C2H3ClO =C9H8O4 +HCl

I came up with 52.0grams of C9H8O4 (aspirin) Is that correct?

Answer 1

C7H6O3 + C2H3ClO -----> C9H8O4 + HCl

moles C7H6O3: 40.0g/ 138g/mol = 0.290 mol
moles C2H3ClO: 30.0g/ 66.5g/mol = 0.451 mol

your limiting reactant is C7H6O3. So, number of moles for your product is only 0.290 moles.

Mass aspirin: 0.290 moles x 180g/mol = 52.2 grams