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A device for training astronauts is designed to rotate the trainee in a horizontal circle of radius 11.5 m. If the force felt by the trainee is 7.18 times her own weight, how fast is she rotating in m/s?

Now express your answer in revolutions per second.

How would you solve this when not given her weight or mass?

2006-11-11 06:29:31 · 3 answers · asked by justinegunderson 1 in Science & Mathematics Physics

3 answers

The answer hippoterr... gave you was OK till the last step. It's always is wise to check the units and see if they make sense. His result is in sec/rev.

2 x Pi x11.5 / 30 = 2.4 He left out the units in the math part, but if you include them you see that the result is in sec/rev.

Unit conversion can be confusing. A better way - you know you want it to be something per sec so start with:

30 meter/sec. Then to convert to rev/sec multiply by 1, in a special form.

In the form 1 rev/(2 x Pi x11.5 meters). This = 1, right? The top and bottom are equivalent. So back to

30 meter/sec * 1 rev/(2 x Pi x11.5 meters) = .415 rev/sec

You understand why weight/mass wasn't needed? It's the acceleration that results from the rotation, and a = F/m.

2006-11-11 08:36:40 · answer #1 · answered by sojsail 7 · 0 0

1

2016-05-03 08:05:22 · answer #2 · answered by Phillip 3 · 0 0

Centripetal acceleration a = v x v / r

a must be 7.81 times that of earth to give a weight as stated

so:

9.81 x 7.81 = v x v / 11.5

V = Sq Rt (9.81 x 7.81 x 11.5) = 30 m/s

In revs per sec:

2 x Pi x11.5 / 30 = 2.4 revs per sec

2006-11-11 07:12:55 · answer #3 · answered by hippoterry2005 3 · 0 0

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