there is a thing called divisibility rules http://mathforum.org/dr.math/faq/faq.divisibility.html
u use them to tell what numbers are divisible by
to tell if a number is prime or composite
http://www.lessonplanspage.com/MathPrimeVsCompositeNumbers7HS.htm
hope this helps you :)
2006-11-11 05:49:59
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answer #1
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answered by avhockey15 2
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A website won't help you on your test.
Any number that ends in 5 is divisible by 5, so it's composite. It's an odd number, so none of the even numbers can be factors. Therefore, it's definitely 5, and possibly 3, 9, or 11 (what happened to 7?).
To test if it's divisible by three, add up all the digits, and if the sum is evenly divisble by 3, the whole number is as well. 5+8+5=18, 18/3=6. So it's definitely 3 too.
These are just shortcuts, though. Take the time, figure it out, and you'll be very happy you did when those tests get handed out.
2006-11-11 05:47:24
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answer #2
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answered by ? 5
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any number is divisible with : 2 if it ends on an even number (2, 78, 90...)
3 if when u + all the numbers get a number that is divisible by 3 (333, 963,6)
5 if the number ends with a 5 or a 0 (50, 70 95)
and a 9 if when u + all the numbers get a number that is divisible by 9 (81,27, 9)
dont know the rest. use a calculator
2006-11-11 05:43:46
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answer #3
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answered by Anonymous
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585 is divisible by 3, 5, and 9, which means its composite. 76 is divisible by 2, and 4, composite. 8001 is prime.
2006-11-11 05:42:58
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answer #4
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answered by L 4
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