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I need a list of about 40 common compounds that I can have my students find their structural formula. The trick is to make it not too easy or too difficult. Examples might be caffene, salisylic acid, Paradichlorobenzene. Can you come up with a few more?

2006-11-11 05:20:42 · 4 answers · asked by The Cheminator 5 in Science & Mathematics Chemistry

4 answers

are they High School students ? 40? that's a lot.. LOLz.. nweiz, hope you'll find this amusing =)

1. alum
2. marijuana
3. aspirin
4. bleach
5. muriatic acid
6. baking soda
7. Borax
8. cream of tartar
9. Epsom salt
10. brimstone
11. Freon
12. milk of magnesia
13. plaster of Paris
14. quartz
15. saltpeter
16. laughing gas
17. tear gas
18. acetone
19. grain alcohol
20. chalk
21. formalin
22. vinegar
23. rubbing alcohol
24. wood alcohol
25. spirit of ammonia
26. asbestos
27. barium white
28. calomel
29. gunpowder
30. diamond
31. galena
32. gypsum
33. oil of wintergreen
34. marble
35. dry ice
36. vitamin C
37. corundum
38. benzol
39. carbonic acid
40. carbolic acid

2006-11-11 05:43:45 · answer #1 · answered by seXy 3 · 0 0

I want i might desire to entice those systems for you, even even with the undeniable fact that the greater suitable consequently of bypass approximately fixing this occasion is to initiate on the suitable suited of the call you have been given. as an social gathering - a) is butane that is composed of four carbons in a immediately chain. once you have your carbons extensive style them a million-4 and then on carbon 2 and on carbon 3 you will upload CH3 communities. finished the form with the help of potential of alongside with in H's the situation ever carbon does not have 4 bonds. Prefixes such at bromo, and chloro purely advise to function the two Br or Cl to that specific carbon. If cyclo is used, your shape is a ring. want this facilitates!

2016-11-23 15:46:02 · answer #2 · answered by Anonymous · 0 0

propane
nonane
trihalomethane
hexane

2006-11-11 05:34:39 · answer #3 · answered by Tsunana 1 · 0 0

ethanol
butane
methane

2006-11-11 05:30:09 · answer #4 · answered by a m 2 · 0 0

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