2006-11-11 05:07:34 · 13 answers · asked by yetisalmn 2 in Sports ➔ Football (American)
no
2006-11-11 05:14:10 · answer #1 · answered by chuck m 1 · 0⤊ 0⤋
No.
Cowboys will upset them next weekend , as the Dolphins upseted the Bears. So the Colts are just hype. The same thing happened last year
2006-11-11 13:22:16 · answer #2 · answered by millsberry nigga 1 · 0⤊ 0⤋
Nope, every week more pressure is added and it will get harder. They still have @Dallas, @Jacksonville(who wants so bad to beat them I bet), and Cincy. I'm sure some might try to argue Philly in there but that is their buisness. On top of all that IF by some almost miracle they get to 15-0 they have Miami waiting for them. You may say it is a home game but no matter how bad Miami is they are playing for their franchise's pride.
2006-11-11 14:45:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I doubt it...they have two more tough games they have to play away from home. The Cowboys aren't going like anything, so they will bring their A game as well.
2006-11-11 13:53:08 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Sure, why not, they will just choke in the playoffs anyway, just like they have done for the past 5 or so seasons
2006-11-11 13:15:08 · answer #5 · answered by Anonymous · 0⤊ 0⤋
With the worst run defense in the league, that is highly unlikely
2006-11-11 13:11:16 · answer #6 · answered by FootballFan1012 6 · 0⤊ 0⤋
their highest record was at 2005 where they made only 14-3, so they could not make it there.
2006-11-11 13:32:05 · answer #7 · answered by Anonymous · 0⤊ 0⤋
for the last time no
2006-11-11 13:12:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋
possible but I doubt it, someone will beat them before the season is over.
2006-11-11 20:48:30 · answer #9 · answered by mister ss 7 · 0⤊ 0⤋
No, it's not their goal, and they won't risk losing starters if they've already clinched homefield.
2006-11-11 13:51:31 · answer #10 · answered by Anonymous · 0⤊ 0⤋
they should have lost to the Jets
2006-11-11 20:00:08 · answer #11 · answered by kiwanis7123 2 · 0⤊ 0⤋