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[4,5,6-----------[1,2,3
7,8,9-----X-----4,5,6
1,2,3]-----------7,8,9]

2006-11-11 02:51:40 · 3 answers · asked by Mr. Knickerbocker 3 in Education & Reference Homework Help

3 answers

Let's say it's like this:
[1 2 3]
[4 5 6] } Pretend the whole thing is surrounded by two big
[7 8 9] brackets

[9 8 7]
[6 5 4] And that the top is multiplied by this
[3 2 1]

[1 2 3]------[9 8 7] (I'm using---as spaces)
[4 5 6]--X--[6 5 4]
[7 8 9]------[3 2 1]
Multiply the first number in row one of the 1st matrix by the first column of the 2nd matrix ( 9 6 3 ). Then multiply the second number in row one by the second column ( 8 5 2 ) and then 3rd number by the 3rd column ( 7 4 1 ). When you're done, you should have the first row of a newer giant matrix set up...

[1(9) + 2(6) + 3(3)---1(8) + 2(5) + 3(2)---1(7) + 2(4) + 3(1)]

Now, take the 2nd row of of the first matrix and multiply it the same way...(now you have the first and second rows I showed you)

[1(9) + 2(6) + 3(3)---1(8) + 2(5) + 3(2)---1(7) + 2(4) + 3(1)]
[4(9) + 5(6) + 6(3)---4(8) + 5(5) + 6(2)---4(7) + 5(4) + 6(1)]

Do you notice a pattern? The column numbers that are multiplied are lined up right on top of each other... this will save you time in the future. The row numbers change, but you know they are always in the same order.
Now, multiply the last row of the first matrix by the columns of the second matrix...(here is how the final matrix looks)

[1(9) + 2(6) + 3(3)---1(8) + 2(5) + 3(2)---1(7) + 2(4) + 3(1)]
[4(9) + 5(6) + 6(3)---4(8) + 5(5) + 6(2)---4(7) + 5(4) + 6(1)]
[7(9) + 8(6) + 9(3)---7(8) + 8(5) + 9(2)---7(7) + 8(4) + 9(1)]

Now, multiply the numbers...
[9 + 12 + 9---8 + 10 + 6---7 + 8 + 3]
[36 + 30 + 18---24 + 25 + 12---28 + 20 + 6]
[63 + 48 + 27---56 + 40 + 18---49 + 32 + 9]

Add up the numbers to get the final resulting matrix...
[30 24 18]
[74 61 54]
[111 114 90]
P.S. Sorry I didn't use your numbers... this is the answer to the matrix I made up, but at least it shows you how to do it right? Hope this helps!!!

2006-11-11 06:08:58 · answer #1 · answered by Mint and Cocoa 2 · 0 0

multiply the digits of the first row of the first matrix to the digits in the column of the second matrix. long story short, you would get this.
[64, 73, 96
102, 126, 150
30, 36, 42]

2006-11-11 03:00:23 · answer #2 · answered by L 4 · 0 0

first raw from first matrix * first column from 2nd matrix that the answer 11 (answer 11 means first column first raw from the answer matrix) then first raw from the 1st into 2nd coulmn from 2nd matrix and thats all u should do it nine times

2006-11-11 04:30:58 · answer #3 · answered by akhokhay 1 · 0 0

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