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You roll five fair, six-sided dice, all at the same time. In that one roll, what is the probability of getting five of the same number?

2006-11-11 02:29:18 · 8 answers · asked by Sasha 2 in Science & Mathematics Mathematics

8 answers

All the possible combinations are found the equation of the number of possible combinations to the power of the number of dice. There are six sides to the 5th power. That comes out to 7776 possible combinations.

There is six possible combination for having all five come up the same number. This means the chances are 6/7776 or 1 in 1296.

2006-11-11 02:40:13 · answer #1 · answered by eric l 6 · 2 1

You cannot just multiply 1/6 by itself 5 times because that would be the probability of getting a specific chosen number from all 5 dice. Since you just said any number the same throughout, there are 6 ways to make that (all 1s, all 2s, etc.).

Therefore, the people who put 1/1296 are correct!

Also, the guy who put the first die doesn't matter so long as the rest match it is correct as well, but his math was off. So you can do:
1 * (1/6) * (1/6) * (1/6) * (1/6) = 1/1296
or
(1/6) * (1/6) * (1/6) * (1/6) * (1/6) * 6 = 1/1296

It works out to the same number: ~0.0007716 or 0.07716%

Brian D, I implore you: please stop answering math questions. You're getting them all miserably wrong! Thermo, your initial problem was written correct, but you solved it wrong. Ms TX, please tell me Math wasn't your pageant skill...

2006-11-11 11:04:39 · answer #2 · answered by C D 3 · 0 0

Think of it this way: Each die can show one of 6 numbers. So the total number of possible combinations is 6^5. Of these, only 6 combinations have all five dice showing the same number. So the probability is 6/6^5, or 1/6^4, or 1 in 1296.

2006-11-11 10:34:14 · answer #3 · answered by Amy F 5 · 2 1

(1/6)^(5-1) = 1 out of 1296
The -1 is because stone one can be any number.

If you want the chance of all the dice show for instance 2,
you get 1 out of 6x1296 = 7776.

Th

2006-11-11 11:06:04 · answer #4 · answered by Thermo 6 · 0 1

each number 1 - 6 has a solution....6 times (5same)(1 diff)
(1/6)^5 * (5/6)^1 * 6
same * different * possibilities =
(1 / 7776) * (25 / 7776) * 6 =
(.0001286) * (.003215) * 6 = .00000248

2 1/2 times per each million rolled

2006-11-11 10:39:31 · answer #5 · answered by Brian D 5 · 0 2

Chance of first dice = 1 (any no.)
2nd,3rd,4th,5th = 1/6

So (1/6)^4 = 1/ 864

2006-11-11 10:36:02 · answer #6 · answered by Anonymous · 0 2

(1/6)(1/6)(1/6)(1/6)(1/6)
just multiply it all together and there's your answer..good luck

2006-11-11 10:33:48 · answer #7 · answered by goldengirl 4 · 0 3

(1/6)(1/6)(1/6)(1/6)(1/6), you multiply

2006-11-11 10:43:05 · answer #8 · answered by J 6 · 1 2

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