The houses along our side of the street are numbered in consecutive odd numbers, the even numbers being on the other side of the street. Our house number is 69, but had the numbering commenced at the other end of the street, our house would be number 40. How many houses are there on our side of the street? Explain how u workd it out! cheers!
2006-11-11 01:06:54 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
54
2006-11-11 02:40:15 · answer #1 · answered by J 6 · 0⤊ 0⤋
Answer: 54.
Solution:
Houses 1-69 odd only gives 35 houses including you. ((69+1)/2)
Houses 2-40 even gives 20 houses including you. (40/2)
Add together, and -1 for counting you twice gives 54 houses on your side of the street.
2006-11-11 09:14:42 · answer #2 · answered by Dravos 2 · 1⤊ 0⤋
there are 35 odd numbered houses including 69 walking up street walking down street there are 20 even numbered houses on your side so there are 35+20-1 ( your house has been counted once already) or 54 houses on your side i believe...
2006-11-11 09:24:43 · answer #3 · answered by ivblackward 5 · 0⤊ 0⤋
54
You are the (69+1)/2 = 35th house on your side of street.
You are directly opposite the 40/2 = 20th house on the other side of the street.
Therefore there muust be 19 houses past your house so 35+19 = 54.
2006-11-11 09:24:01 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
54
2006-11-11 09:26:31 · answer #5 · answered by Dr. J. 6 · 0⤊ 0⤋
69-1 /2 = 34 + 40/2 20 minus 1 because yiur house was countwed twice so 53
2006-11-11 09:45:18 · answer #6 · answered by reen 2 · 0⤊ 0⤋