2006-11-10 20:24:29 · 4 answers · asked by mask 1 in Science & Mathematics ➔ Chemistry
The oxidation state of Vanadium in the NH4VO3 complex is +5 because oxygen has a -2 charge and NH4 has a +1 charge. 3 oxygens give you a -6 charge from oxygen. -6+1=-5. Since the complex is a neutral complex, vanadium would have to be +5 to match.
2006-11-10 21:24:00 · answer #1 · answered by r2data 2 · 0⤊ 0⤋
I HOPE ALL THE FOLLOWING STEPS CAN HELP YOU CLEA LY.
N= (-3). H=1X4 =+4. V= THE UNKNOWN. O=(-2)X3 =(-6)
therefore NH4VO3 is calculated as following.
N+H4+V+O3
(-3)+4+V+(-6) = 0
V+4+(-3)+(-6) =0
V+4+(-9) =0
V+4-9 =0
V-5 =0
V=+5. therefore V =+5
I HOPE THESE AS EXPLAIN IT WELL
2006-11-11 00:26:33 · answer #2 · answered by Tosin A 2 · 0⤊ 0⤋
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2016-12-17 08:13:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Vanadium in the ion (VO3)- is behaving as if it has a +5 charge.
2006-11-10 20:40:45 · answer #4 · answered by Gervald F 7 · 0⤊ 0⤋