A ball is thrown at an angle of 66.0 degrees above the horizontal with an initial velocity of 4.47 m/s.?

Question

What is the maximum height the ball attains?

There are four choice... Please Help!!!

1.532 m

1.698 m

0.849 m

2.55 m

Answer 1

For launch velocity
v0 = 4.47 m/s,
launch angle
θ = 66 degrees,
The horizontal range is
R = 1.515173718712374 m.
The total time of flight is
t = 0.83337718278825 s.
The peak height is
h = 0.8507839727702984 m.

Answer 2

Given: initial velocity at 66 degrees above the horizontal=4.47m/s.

Imagine that at the top of the trajectory, you drop a ball. At this point the vertical component of its velocity, u=0. When the ball hits the ground its velocity is equal to but opposite in the direction to the vertical component of its velocity when it was launched. This is a basic concept that you have to keep in mind. The distance travelled by the ball which we had dropped from the top of its trajectory, s, is our unknown. Now use the formula:

v^2-u^2=2as

where v is equal to the vertical component of the velocity of the ball when it was launched (but opposite in direction), u is the vertical component of the velocity at the top which we said is equal to 0, a is the acceleration of gravity of 9.8m/s^2, and s is our unknown.

Now substitute known values:

(4.47sin66)^2-0=2*9.8s
s=(4.47^2*0.914^2)/2*9.8
=0.85m

maybe your teacher is using more than 3 digits as the value of sin66. I'm using only 3; that's why my answer is 0.85m not 0.849m. If you have a scientific calculator find the value of sin66 up to 5 digits. Then substitute in our formula and see if you get exactly 0.849m.

Answer 3

First, how long will the ball proceed to be in the air? Its vertical component to action would be approximately 33 m/s, so use the equation 0 = 33 m/s + (-9.8 m/s²) t. The ball will attain its maximum element at t (3.4 s) and could hit the floor at 2t (6.8 s). From there, you will locate horizontal displacement with the equation ?x = (60 m/s * sin 33°) (6.8 s). Your answer would be 340 m taking significant figures into consideration. somewhat a force!

Answer 4

v=v0+at
0=4.47sin(66)-9.81(t)
t=4.47sin(66)/9.81=.41626seconds

x=vt+(1/2)at^2
x=(4.47)sin(66)(.41626)-(1/2)(9.81)(.41626^2)
x= 1.6998-.8499
x=.8499m =>.849m

Answer 5

2.55m