math questions...?

Question

1.) when a weight is attached to a spring, the spring is streched a distance proportional to its weight. if a 2kg. weight stretches a certain spring 1.2cm,how much would a 9-kg weight stretch the spring,assuming the elastic limits of the spring are not exceed? (ANSWER USING DIRECT VARIATION)





2.)the time required for one complete swing of a pendulum is called the period of the pendulum. the period varies directly as the square root of its length.A 1 metre pendulum has a period of 1 second. what will be the lenght of a pendulum w/ a period of 2 seconds?
(ANSWER USING DIRECT VARIATION)

Answer 1

1.2cm : 2kg as X cm : 9 kg
1.2/2 = x/9
multiply both sides by 9
5.4 cm = x

1m/1sec = sr x/2
square both sides
1= x/4
multiply both side by 4
4m = x

Answer 2

I see your blend up - A = PiR^2 precise? properly, section = Pi (radius squared), the place you positioned the radius as 40 8. The Diameter is 24 cm, precise? properly, interior the formula, radius is barely 0.5 of the diameter, so which you ought to be utilising 12^2, no longer 40 8^2 Your formula ought to look like this: section = Pi(3.14) * 12^2 That'll provide you the ultimate suited answer.

Answer 3

x/9g = 1.2cm/2g
x = 0.6*9 = 5.4 cm

2/√x = 1/ √1
√x = 2
x = 4 m

Answer 4

since F=kx
and F=ma
ma=kx
a=g
so mg=kx
since g is constant, let k/g=K
so m=Kx
lets solve for K first
K=m/x=2/1.2=1.666666

now solve for x
m=Kx
x=m/K=9/1.666666666=5.4cm

b)4meters

Answer 5

1. 5.4 cm

2. 4 m

Answer 6

i couldnt help u im failing math ritee now i hate it so much