x times the square root of 3 + 4 = 7 = the square root of 3?

Question

The instructions say to solve the equation. I can't figure it out!

Please help.

CORRECTION

It's supposed to be:

x times the square root of 3 + 4= 7 + the square root of 3.

For the 3 people that replied so far, maybe I didn't describe the question so well.
It should be:
/- = Square root
x/-3 + 4=7 + /-3

x√3 + 4 = 7 + √3

Answer 1

x(sqrt)3+4=7+(sqrt)3
=>x(sqrt)3-(sqrt)3=7-4=3
(sqrt)3} (x-1)=3
3(x-1)=3(sqrt)3 [multiplying both sides by (sqrt)3]
x-1=(sqrt)3 [cancelling or dividing both sides by 3]
x=1+(sqrt)3 ans

Answer 2

x* sqrt (3) +4 = 7 +sqrt (3)
x*sqrt (3)+4=7+sqrt (3) : x=2.732051

ok lets go!
move the 4 over to the other side (becomes negative)
x*sqrt(3)=(7-4)+sqrt(3)
add the negative 4 to the 7 (equals 3)
x*sqrt(3)=3+sqrt(3)
move the sqrt(3) to the other side by dividing both sides by sqrt(3)

x=(3+sqrt(3))/sqrt(3)
that can be made into to fractions 3/sqrt(3) + sqrt(3)/sqrt(3)
so now you have (3/sqrt(3))+1
and 3/sqrt(3) = sqrt(3)
so your final ans is 1+sqrt(3)
and that is aprox 2.732050808

Answer 3

x(3+4) = 7+ √3

square the equation

x^2 (3+4)^2 = (7+√3)^2
x^2 (7)^2 = (7)^2 + 3
x^2 (49) = 49 +3
49 x^2 = 52
x^2 = 52/49
x = √(52/49
x = ((√52)/(√49))
x = (√52)/7

Answer 4

one million. 3sqrt2x + xsqrt8x - 5sqrt18x = 3sqrt2x + xsqrt4*2x - 5sqrt9*2x = 3sqrt2x + 2xsqrt2x - 15sqrt2x = 2xsqrt2x - 12sqrt2x Nakim mistook -12 cases the sq. root of 2x for -12x cases the sq. root of 2x. The expression is already simplified, yet you ought to team likes collectively 2xsqrt2x - 12sqrt2x = (2x -12)sqrt2x

Answer 5

x= [(3+ the square root of 3)(square root of 3)]/3

work:
x(square root of 3)+4=7+ (square root of 3)

x(square root of 3)=3 + (square root of 3)

x= [4+the square root of 3]/ (square root of 3)
then i multiplied the numerator and the denominator by the square root of 3 to rationalize the denominator (to get rid of the square root in the denominator) becuase square root of 3 divided by square root of 3 equals 1 to get:

x= [(4+ the square root of 3)(square root of 3)]/3

Answer 6

let the no be x.
thus
x(3+4)^2=7+3^2
or x(7)^2=7+9
or x*49=16
or x=16/49(ans)
good luck!!!!!!!!

Answer 7

xrad7=7=rad3?????