Please hellp!?

Question

Can anyone help me factor 2x^2-14x+20
I am having trouble with the steps

Answer 1

Compare it with,
Ax^2 + Bx + C = 0

So, A = 2
B = -14
C = 20.

Now solve for solution as,

x = [ -B ( B^2 - 4AC ) ^1/2 ] / [ 2A ]

So, x = [14 (36)^1/2] / 4
x = [14*6] / 4
x= 84 / 4
x = 21..

Note: when we take root of 36, ans is + or - 6
So,
x = +21 or -21