Write an equation of the line that passes through the given point and has the given slope...?

Question

Quite simply--I'm clueless..

I have 32 problems like this, I just need to see the set up of one and I can figure it out.. Thank you so much in advance =)

16.) (2, -7) m = -1/5

Answer 1

Hey, here's the setup for these types of problems.
You want the equation in the form of y = mx + b
since we know that x = 2, y = -7, and m = -1/5, we can plug these values into that equation to find the equation of the line that passes through the desired point. SO:
-7 = (-1/5)(2) + b
-7 = (-2/5) + b
b = (-7)+(2/5)
b = -33/5
so the equation for the line is:
y = (-1/5)x - (33/5)

hope that helps!!

Answer 2

LOL...sometimes I'm clueless too!

The standard form for a linear equation is:

y = mx+b where m is the slope and b is the y intercept(the value of y when x = 0)

So plug the value of m = -1/5 and the values of x and y from the given point (2,-7) into the equation, so you can determine the value of b.

-7 = (-1/5)*2 +b

b = -7 + 2/5

b = - 35/5 + 2/5 = -33/5

So the equation to the line is:

y = (-1/5)x - 33/5

or simplifying:

y = -1/5(x+33)

Answer 3

Given a point (2, -7) and the slope of a line m = - 1/5, we can use the point-slope equation of a line defined as follows:
(y - y0) = m(x - x0),

where (x0, y0) is the given point and m is the slope of a line. Thus, we have:

y - (-7) = -(1/5) * (x - 2)

Hence, we write this in the slope-intercept form as follows:
y = -(1/5) * (x - 2) + 7
   = -(1/5)x + (2/5) + 7
   = -(1/5)x + (2/5 + 35/5)
   = -(1/5)x + (37/5).

Therefore, the equation of a line that passes through the given point (2, -7) with a slope of -1/5 is defined by y = -(1/5)x + (37/5).

Answer 4

You are looking to write an equation of the form

y = mx + b

You are given m and you need to figure out b by plugging in the values given for x and y.

In your example:

y = (1/5)x + b

-7 = (1/5)2 + b

-7 = 2/5+ b

b = -37/5

So the equation is

y = (1/5)x - 37/5

Hope that helps.

Answer 5

Well for a line
y = mx + b

m = -1/5
So y = -1/5 x + b
When x = 2 y = -7

So -7 = -1/5 * 2 + b
b = -7 + 2/5
= -33/5
So y = -x/5 -33/5
OR x + 5y + 33 = 0 (on multiplying all by 5 and siimplifying)

Answer 6

The basic form is y=mx+b. You have m and (x,y). Just substitute in those values and solve for b.

Here -7=(-1/5)2+b. It becomes -7=-2/5 +b. b=-33/5
So the equation is y=(-1/5)x-(33/5)

Answer 7

y=mx+b
b is the y intercept.
m is the slope
and the points have to be put into the equation to find b
so (2, -7) is plugged in so the equation is -7=(-1/5)(2)+b
so it's -7=-.4+b b= -6.6 so, the equation is y= -1/5x-6.6
i think this is the answer, if not i'm terribly sorry. but, you can check it using a graphing calculator.

Answer 8

use the point slope form: y-y1=m(x-x1) where y is the y- intercept, y1 is the y point given, m is the slope, x is the x intercept and x1 is the x point given . ex:

(2,-7) m= -1/5

y-(-7)= -1/5 (x-2)
y+7 = -1/5x + 2/5
-7 -7
y= -1/5x -6 3/5

you always solve to where you have y= something.
hope that helps!

Answer 9

Use the ff equation:
y-y1=m(x-x1) with x1=2; y1=-7 and m=-1/5

Substitute the given

y--7= -1/5(x-2)
y+7=-1/5x+2/5
5(y+7)= 5(-1/5x+2/5)
5y+35= -x+2
x+5y= -33

Answer 10

use the equation
y = mx + b
plug in the number you have into this equation
-7 = (-1/5)(2) + b
b = -33/5

thus the equation is
y = (-1/5)x - (33/5)