Last math Question?

Question

The perimeter of a rectangular writing pad is 28 inches. The length is 1 inch less than twice the width. Find the width.

Answer 1

length = 2 width - 1
perimeter = 6 width - 2
28 = 6 width - 2
6 width = 28 + 2
6 width = 30
width = 5

Answer 2

W = 5

Answer 3

let w - be the width of the reactangle,
2w-1 - will be the length since the problem says 1 inch less than twiwe the width.

2(w) + 2(2w-1) = 28
solving for w:
2w + 4w - 2 = 28
6w - 2 (+2) = 28 (+ 2)
6w = 30
w = 5.

thus, the width is 5 inches

Answer 4

The Preimeter formula is

P = 2L + 2W

28 = 2(2W - 1)+ 2W

28 = 4W - 2 + 2W

28 + 2 = 6W - 2 + 2

30 = 6W

30/6 = 6W/ 6

5 = W

The answer is W = 5

Insert th W value into the equation

- - - - - - - - - - - - - - - - - - - - - - -

P = 2L + 2W

P = 2(2W - 1) + 2W

28 = 2[2(5) - 1] + 2(5)

28 = 2[10 - 1] + 10

28 = 2[9] + 10

28 = 18 + 10

28 = 28

- - - - - - - - - - - - - - - - - - - - -

The width is 5 inches

- - - - - - - -s-

Answer 5

width = 5

Answer 6

L=2W-1
=>L-2W=-1
2L+2W=28
adding
3L=27
L=9
sub W=5
check the perimeter=2(9+5)=28

Answer 7

5 inches

Answer 8

the with is 18

Answer 9

perimeter of a rectangle is twice the width plus twice the length, or 2w + 2L and is 28

L + 1 = 2W
2W + 2L = 28

Rewrite:
L - 2W = -1
2L + 2W = 28

now add

3L + 0 W = 27
3L = 27
L = 9

now substitue:

2L + 2W = 28
18 + 2W = 28
2W = 10
W = 5

Answer 10

The diagonal AC divides the parallelogram into two congruent right triangles--CAB and ACD. CAB is a right triangle with BC the hypotenuse. (AC)² = (BC)² - (AB)² = 13² - 12² = 169 - 144 = 25 AC = 5 Calculate the area of triangle CAB. Area = ½bh = ½*AC*AB = ½*5*12 = 30 Triangle ACD is congruent to triangle CAB so the area of the parallelogram ABCD is: 2*30 = 60 cm²