Solve the equation for x. 2(x - 5)^2 = 3?

Question

Solve the equation for x.

2(x - 5)^2 = 3

Answer 1

2(x - 5)^2 = 3
So (x - 5)^2 = 3/2
Thus x - 5 = ± √(3/2)
= ± √6 / 4

Thus x = 5 ± √6 / 4

Answer 2

Foil out the (x-5)^2:
2(x^2-10x+25)=3

Distributive property:
2x^2-20x+50=3

Subtract 3 on both side to set it to zero:
2x^2-20x+47=0

You want to use the quadratic formula:
x=-b±√b^2-4ac/2a
20±√(20)^2-4(2*47)/2(2)
20±√400-4(94)/4
20±√(400-376)/4
(20±2√6)/4

Answer 3

since you have ^2 this means you have 2 (x-5)
it will look like this
2(x-5)(x-5) =3

you would do this step called foil

F-first
o- outer
i- inner
l - last

2x + 2x - 10 + 25 = 3

combine like terms

4x + 15 =3

subtract the 15 over to the 3 side

4x = -12

divide the 4 over

x = -3

I think this is correct it has been a loooong time since i did math

Answer 4

2(x - 5) ^ 2 = 3
2(x^2 - 10x + 25) = 3
2x^2 - 20x + 50 = 3
2x^2 - 20x + 47 = 0

Now use the quadratic formula by following this format (ax^2 + bx + c)
( - b + (or - ) sq rt(b^2 - 4ac)) / 2a
(20 + (or - ) sq rt(400 - 376)) / 4 = (20 + (or - ) sq rt (24))/4
(20 + (or - ) 2 * sq rt (6))/4

round answers
x = 6.225
x = 3.775

Answer 5

2(x^2 - 10 x + 25)=3
2x^2 - 20 x + 47 = 0

then use quadriatic formula

Answer 6

2(x - 5)² = 3

(2x - 10)² = 3

2x - 10 = ± √3

2x - 10 + 10 = 10 ± √3

2x / 2 = 10/2 ± √3/2

x = 5 ± √3/2

- - - - - -s-

Answer 7

all you need to do is "undo" the operations:

step 1: divide bothe sides by 2
step 2: obtain the square root of both sides
step 3: add 5 to both sides
step 4: if needed, rationalize the result.

in all, x = sqrt(3/2) + 5
after rationalization:
x = [sqrt(6) + sqrt(10)]/2

Answer 8

foil
2(x-5)(x-5)=3
2(x^2-10x+25)=3
parenthesis
2x^2-20x+50=3
subtract 3 on both sides
2x^2-20x+47=0
use the quadratic formula, and you can figure out the rest

Answer 9

you have one answer from this question already right which is -2 so if you do synthetic division you will eventually get (x+2)(x^2+1) = 0 So there fore the other two answers are x = +/- i, in which " i " is an imaginary number Maths rock :)

Answer 10

2(x^2-10x+25)=3
2x^2-20x+50=3
2x^2-20x+47=0

x=[20 +/- sq.root (400-4(2)(47)] / 4

x=[20 +/- 2 sq.root 6]/4

x=[10 +/- sq.root 6]/2