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2(-a^n b)^3 * (-1/2a^n b^2)^3

(3^3a*9^2a-4*27^3-a) / (81^a-1)

Can you help me simplify them???

2006-11-10 12:01:50 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

(2)(-1/2)^3
=(2)(-1/8)
=-1/4
-a^(3n)*a^(3n)=-a^(6n)
b^3*b^6=b^9
so the answer is
-1/4a^(6n)*b^9

2006-11-10 12:16:39 · answer #1 · answered by raj 7 · 0 0

For the first, you need to cube everything but the 2, and then simplify. Remember a negative cubed is still negative.

For the second one, rewrite everything in terms of base 3. Also, use the rule a^m/a^n=a^(m-n). Your notation is bad enough that I can't solve it for you, though I have a guess.

2006-11-10 12:16:17 · answer #2 · answered by zex20913 5 · 0 0

I need a few clarifications. Could you update the question with a bunch more parentheses? This is very hard to read.
Is that -a^nb or -a^n * b?
Is that -1/(a^n *b^2) or (-1/a^n) * b^2 or -1/(a^(n * b^2))?
If you fix the problems like that I might be able to help.

2006-11-10 12:13:50 · answer #3 · answered by incorrigible_misanthrope 3 · 0 0

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2016-11-23 14:51:02 · answer #4 · answered by ? 4 · 0 0

i think i got the first one:
(.25)(a^(6n))(b^a)
im not sure about the second one.
i need more time to do it

2006-11-10 12:20:42 · answer #5 · answered by trackstarr59 3 · 0 0

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