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How can we graph a function with respect to Y on a graphing calculator: ie. X=Y^2+2Y

2006-11-10 11:40:32 · 5 answers · asked by mn1998 2 in Science & Mathematics Mathematics

5 answers

X = Y^2 is not a function. It fails the vertical line test. You cannot graph it on a graphing calculator. (At least not a TI-86.)

You need to break it into two pieces that don't have multiple y values per x value. In this case, x = y^2 breaks nicely into
y = square root of x
and y = - square root of x

As far as I know, you can't graph X as a function to Y on any TI graphing calculators, but I only know up to the TI-89. You can simulate a graph of a f(y) = x equation but you have to convert it into a piecewise function.

2006-11-10 11:52:16 · answer #1 · answered by incorrigible_misanthrope 3 · 0 0

Here is a DreamCalc Financial Graphing Calculator
http://www.goldenmouse.net/Mathematics.html

With DreamCalc, you'll be able to graph functions and plot list data more simply than ever before. In fact, it is a match for many dedicated graphing packages, but far easier to use.

2006-11-10 12:02:25 · answer #2 · answered by Allen 2 · 0 0

X=Y^2 + 2Y
Is just like
Y=X^2 + 2X
if you switch the variables. So, just graph that, and switch the X and Y values.

2006-11-10 11:45:25 · answer #3 · answered by Anonymous · 0 0

if y is the dependent variable,
Y^2 + 2Y - Z = 0
Y = -1 + √(1 + X), and
Y = -1 - √(1 + X).

2006-11-10 11:51:39 · answer #4 · answered by Helmut 7 · 0 0

what's sin(36degrees 40 8)? purely set it do degree mode, and each and each and every time sins and such comes up purely placed the decision without the ranges theres no aspect in puting ranges image in ranges mode

2016-11-29 00:30:53 · answer #5 · answered by england 4 · 0 0

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