cant remember algebra...1y = 7y ---- 8?

Question

been out of school too damn long, how the heck do you solve these critters?

Answer 1

not sure what your question is, but here's a quick n' dirty to solving simple algebraic equations:

we'll use this simple equation 5 - x = 4x


step 1: get all your variables on one side of the = and constants on the other... think of the = as a balance point on a balance scale... you can do anything to one side, and as long as you do it to the other, it will stay balanced!

so to get the x from 5 - x to the other side, we need to add an x to both sides: 5 - x + x = 4x + x, 5 - 0 = 5x, 5 = 5x

step 2: get the variable down to one multiplier

we know what 5x is, but we want to know x... so how do we find out? Well, since we know what 5 times x is, we can divide this by 5 to get x. But, we want to stay "balanced" so we have to divide both sides by 5:

5x / 5 = 5 / 5
x = 1

Voila! Solved :)

Hope this helps.

Answer 2

If you mean
1y = 7y (-1)(-1)(-1)(-1) 8
Then:
(We assume that there is a one in front of the variable if there is none listed.)
y = 7y + 8
move over 7y by subtracting it from both sides to collect common terms.
y-7y = 8
-6y = 8
divide it all by the coefficient in front of the variable
(-6y = 8)/(-6)
y = -8/6

Answer 3

The answer is 1.33333y.
work:
1y = 7y ---- 8?
8+1y=7y
8=6y

Answer 4

if your question was 1y = 7y - 8 then it would be:
1y - 7y = -8
-6y = -8
y = -8/-6
y= 4/3

Answer 5

y=7y-8
first subtract 7y in both sides to get y in one side
y = 7y - 8
-7y -7y

ur left w/ -6y=-8
divide by -6
and y = 4/3

Answer 6

If the ------------ means+, then you first subtract 7y from each side and get -6y = 8 . Next divide each side by -6 and y = -4/3

If the------------means -, then you first subtract 7y from each side and get -6y = -8. Divide each side by -6 and y = 4/3

Answer 7

1y=7y-8
-7y=-7y-8
-6y= -8

y= -8/-6